I got this result:
Code:
. boxtid logistic borrelia age Iteration 0: Deviance = 1030.56 Iteration 1: Deviance = 1030.559 (change = -.000988) -> gen double Iage__1 = X^1.9267-22.98836857 if e(sample) -> gen double Iage__2 = X^1.9267*ln(X)-37.40487309 if e(sample) (where: X = age/10) [Total iterations: 1] Box-Tidwell regression model Logistic regression Number of obs = 1510 LR chi2(2) = 32.12 Prob > chi2 = 0.0000 Log likelihood = -515.27909 Pseudo R2 = 0.0302 borrelia Odds Ratio Std. Err. z P>z [95% Conf. Interval] Iage__1 1.029305 .1032665 0.29 0.773 .8455632 1.252974 Iage_p1 1.001444 .0455013 0.03 0.975 .916119 1.094717 age .0281323 .0052322 5.377 Nonlin. dev. 0.822 (P = 0.365) p1 1.926708 1.310557 1.470 Deviance: 1030.559.
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