Code:
* Example generated by -dataex-. To install: ssc install dataex clear input byte id int year str1 industry float x str6 name float(fq_x w) 1 2008 "A" 1 "张三" 1 0 2 2008 "A" 1.2 "张三" 1 0 8 2008 "A" 1.4 "孙七" 1 0 3 2008 "A" 1.5 "王八" 2 0 4 2008 "A" 1.8 "李四" 2 0 7 2008 "A" 1.6 "李四" 2 0 5 2008 "A" 2 "赵五" 3 2 6 2008 "A" 2.2 "张三" 3 2 9 2008 "A" 2.5 "赵五" 3 2 10 2008 "A" 2.6 "陈九" 4 0 11 2008 "A" 2.8 "李四" 4 0 15 2008 "A" 2.6 "赵五" 4 0 12 2008 "A" 3.7 "王八" 5 0 13 2008 "A" 3.5 "陈九" 5 0 14 2008 "A" 3.3 "李四" 5 0 16 2008 "B" 1 "张三" 1 0 17 2008 "B" 1.2 "李四" 1 0 23 2008 "B" 1.4 "赵五" 1 0 18 2008 "B" 1.5 "孙七" 2 1 19 2008 "B" 1.8 "赵五" 2 1 22 2008 "B" 1.6 "孙七" 2 1 20 2008 "B" 2 "陈九" 3 1 21 2008 "B" 2.2 "李四" 3 1 24 2008 "B" 2.5 "陈九" 3 1 25 2008 "B" 2.6 "李四" 4 1 26 2008 "B" 2.8 "王八" 4 1 30 2008 "B" 2.6 "孙七" 4 1 27 2008 "B" 3.7 "陈九" 5 2 28 2008 "B" 3.5 "李四" 5 2 29 2008 "B" 3.3 "赵五" 5 2 31 2009 "A" 1 "张三" 1 0 32 2009 "A" 1.2 "李四" 1 0 38 2009 "A" 1.4 "赵五" 1 0 33 2009 "A" 1.5 "孙七" 2 1 34 2009 "A" 1.8 "赵五" 2 1 37 2009 "A" 1.6 "孙七" 2 1 35 2009 "A" 2 "陈九" 3 1 36 2009 "A" 2.2 "李四" 3 1 39 2009 "A" 2.5 "陈九" 3 1 40 2009 "A" 2.6 "李四" 4 1 41 2009 "A" 2.8 "王八" 4 1 45 2009 "A" 2.6 "孙七" 4 1 42 2009 "A" 3.7 "陈九" 5 2 43 2009 "A" 3.5 "李四" 5 2 44 2009 "A" 3.3 "赵五" 5 2 46 2009 "B" 1.2 "赵五" 1 0 47 2009 "B" 1.5 "张三" 1 0 52 2009 "B" 1.4 "李四" 1 0 48 2009 "B" 1.8 "李四" 2 1 49 2009 "B" 2 "孙七" 2 1 51 2009 "B" 1.6 "陈九" 2 1 50 2009 "B" 2.2 "赵五" 3 2 53 2009 "B" 2.5 "孙七" 3 2 54 2009 "B" 2.6 "赵五" 3 2 55 2009 "B" 2.8 "陈九" 4 1 59 2009 "B" 2.7 "李四" 4 1 60 2009 "B" 3.2 "陈九" 4 1 56 2009 "B" 3.7 "李四" 5 1 57 2009 "B" 3.5 "王八" 5 1 58 2009 "B" 3.3 "陈九" 5 1 end
- For each year and industry, how can we count the number of same names (`name') in other `fq_x' group. For instance, for fq_x=1, we want find the number of same names (张三,张三,孙七) in other fq_x=2,3,4,5 groups. Similar procedures apply to fq_x=2. In this case, we want find the number of same names (王八,李四,李四) in other fq_x=1,3,4,5 groups.
- If you have problem in recognizing Chinese, I can modify the data (name) into English. Thanks.
- `w' is the desired results.
0 Response to count *same names*in other groups?
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