I am interested to analyze bmizpre over time by gender, drug, "bmicategory " and "diseasetype" with random effects for subject.
My question is do I have to run different univariate model included time, the covariate, and the interaction between time and the covariate ?
This is the command that I used:
Code:
mixed bmizpre gender##c.point || ptid: point
Following is the output
Code:
mixed bmizpre gender##c.point || ptid: point Performing EM optimization: Performing gradient-based optimization: Iteration 0: log likelihood = -46.530546 Iteration 1: log likelihood = -45.773561 Iteration 2: log likelihood = -45.698352 Iteration 3: log likelihood = -45.698038 Iteration 4: log likelihood = -45.698038 Computing standard errors: Mixed-effects ML regression Number of obs = 32 Group variable: ptid Number of groups = 16 Obs per group: min = 2 avg = 2.0 max = 2 Wald chi2(3) = 1.46 Log likelihood = -45.698038 Prob > chi2 = 0.6918 -------------------------------------------------------------------------------- bmizpre | Coef. Std. Err. z P>|z| [95% Conf. Interval] ---------------+---------------------------------------------------------------- 1.gender | .1375 .5429129 0.25 0.800 -.9265897 1.20159 point | .225625 .1912063 1.18 0.238 -.1491324 .6003824 | gender#c.point | 1 | -.179375 .2704065 -0.66 0.507 -.709362 .350612 | _cons | -.21125 .3838974 -0.55 0.582 -.9636751 .541175 -------------------------------------------------------------------------------- ------------------------------------------------------------------------------ Random-effects Parameters | Estimate Std. Err. [95% Conf. Interval] -----------------------------+------------------------------------------------ ptid: Independent | var(point) | 1.06e-18 1.40e-17 6.07e-30 1.86e-07 var(_cons) | .5940602 .3300578 .1999428 1.765042 -----------------------------+------------------------------------------------ var(Residual) | .5849574 .2068139 .2925356 1.169687 ------------------------------------------------------------------------------ LR test vs. linear model: chi2(2) = 4.69 Prob > chi2 = 0.0960 Note: LR test is conservative and provided only for reference.
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