Hi All,

I'm using STATA 15.

My question: Would someone know how to report the 95% confidence interval for the random-intercept's standard deviation in ESTTAB?

My code is below -- please let me know if I can clarify. Thank you for your time!

Code:
. eststo: mixed absenty_p bmim || grade: 

Performing EM optimization: 

Performing gradient-based optimization: 

Iteration 0:   log restricted-likelihood =    3883.39  
Iteration 1:   log restricted-likelihood =    3883.39  

Computing standard errors:

Mixed-effects REML regression                   Number of obs     =      2,676
Group variable: grade                           Number of groups  =          9

                                                Obs per group:
                                                              min =        225
                                                              avg =      297.3
                                                              max =        343

                                                Wald chi2(1)      =       0.11
Log restricted-likelihood =    3883.39          Prob > chi2       =     0.7432

------------------------------------------------------------------------------
   absenty_p |      Coef.   Std. Err.      z    P>|z|     [95% Conf. Interval]
-------------+----------------------------------------------------------------
        bmim |   .0000674   .0002057     0.33   0.743    -.0003357    .0004705
       _cons |   .0563113   .0051681    10.90   0.000      .046182    .0664406
------------------------------------------------------------------------------

------------------------------------------------------------------------------
  Random-effects Parameters  |   Estimate   Std. Err.     [95% Conf. Interval]
-----------------------------+------------------------------------------------
grade: Identity              |
                  var(_cons) |   .0000689   .0000403      .0000219    .0002167
-----------------------------+------------------------------------------------
               var(Residual) |   .0031651   .0000867      .0029996    .0033396
------------------------------------------------------------------------------
LR test vs. linear model: chibar2(01) = 31.86         Prob >= chibar2 = 0.0000
(est5 stored)

esttab using "/Users/maishahuq/Desktop/BMI-A-A/LDA_bmi_absenty_p.csv", replace se transform(ln*: exp(@) exp(@))