Sorry for basic question. I would like to translate the following date into Stata date format.
Code:
* Example generated by -dataex-. To install: ssc install dataex clear input str6 dscd str8 date "ID:AAL" "10101990" "ID:AAL" "10111990" "ID:AAL" "1011990" "ID:AAL" "10121990" "ID:AAL" "10151990" "ID:AAL" "10161990" "ID:AAL" "10171990" "ID:AAL" "10181990" "ID:AAL" "10191990" "ID:AAL" "1021990" "ID:AAL" "10221990" "ID:AAL" "10231990" "ID:AAL" "10241990" "ID:AAL" "1031990" "ID:AAL" "1041990" "ID:AAL" "1051990" "ID:AAL" "1081990" "ID:AAL" "1091990" "ID:AAL" "1101990" "ID:AAL" "11101989" "ID:AAL" "1111990" "ID:AAL" "11131989" "ID:AAL" "11141989" "ID:AAL" "11151989" "ID:AAL" "11161989" "ID:AAL" "11171989" "ID:AAL" "111990" "ID:AAL" "11201989" "ID:AAL" "11211989" "ID:AAL" "1121990" end
I tried both:
Code:
gen date2 = date(date, "MDY") format date2 %td
Code:
numdate daily date3 = date, pattern(MDY)
Best regards,
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