Hello everyone,
I´ve been asked to show that, when you run your outcome variable against your geographical fixed effects, the adjusted R squared equals 1.
The idea behind this is that, as your database is in that unit of analysis when running:
reg y i.spatial_fixed_effect
you should get that that spatial fixed effects explain all the variance you have.
I have tried several times with a dataset but haven´t succeed.
Has anyone proved this with a constructed database so I can take a look at it?
Thank you very much,
Regards
Sara R
Related Posts with R squared equals 1 when running spatial fixed effects
Multiple Fixed Effects with Regression reghdfeHi everyone, I am now replicating the paper of Kumar et. al (2021). Social Learning and Analyst Be…
xtabond2 vs xtdpdgmmHello, I'm trying to study the spillover effect of trading with Arab Spring countries on economic gr…
occures error 111 during decomp for heckman reg.Hi All, Kindly help me to solve this problem. I am trying to run decomposition using decomp for the…
the criteria of choiceHello I hope you are doing well. I have a question, please, about the criteria for choosing between …
How to deal with unequal variance - mixed effects linear regressionHello, I have run a linear mixed model to test the within-subject difference in activity behaviours…
Subscribe to:
Post Comments (Atom)
0 Response to R squared equals 1 when running spatial fixed effects
Post a Comment