I would like to ask you please some help interpreting margins
I use Stata 14. What I did is
Code:
logit diabetes i.bmicatasia agegroup2 fobp2 sexr
bmicatasia is BMI category
agegroup2 is age-group
fobp2 is blood pressure category
and sexr is sex
HTML Code:
. logit diabetes i.bmicatasia agegroup2 fobp2 sexr
Iteration 0: log likelihood = -565.88314
Iteration 1: log likelihood = -475.64377
Iteration 2: log likelihood = -411.65553
Iteration 3: log likelihood = -409.32254
Iteration 4: log likelihood = -409.30833
Iteration 5: log likelihood = -409.30833
Logistic regression Number of obs = 1,904
LR chi2(5) = 313.15
Prob > chi2 = 0.0000
Log likelihood = -409.30833 Pseudo R2 = 0.2767
diabetes Coef. Std. Err. z P>z [95% Conf. Interval]
bmicatasia
Over 1.112465 .2561249 4.34 0.000 .6104693 1.614461
Obese 2.073727 .2269948 9.14 0.000 1.628826 2.518629
agegroup2 -.0525809 .198183 -0.27 0.791 -.4410124 .3358506
fobp2 1.288137 .1236135 10.42 0.000 1.045859 1.530415
sexr -.4397445 .1989234 -2.21 0.027 -.8296272 -.0498618
_cons -4.503091 .2703448 -16.66 0.000 -5.032957 -3.973225
HTML Code:
. margins bmicatasia, at(fobp2==0 sexr==0 agegroup2==0) post
Adjusted predictions Number of obs = 1,904
Model VCE : OIM
Expression : Pr(diabetes), predict()
at : agegroup2 = 0
fobp2 = 0
sexr = 0
Delta-method
Margin Std. Err. z P>z [95% Conf. Interval]
bmicatasia
Normal .0109534 .0029288 3.74 0.000 .0052131 .0166937
Over .0325897 .0094497 3.45 0.001 .0140686 .0511108
Obese .0809608 .0205576 3.94 0.000 .0406686 .121253
HTML Code:
. tab diabetes bmicatasia if fobp2==1 & sexr==0 & agegroup2==0
BMI Asia
diabetes Normal Over Obese Total
0 10 7 5 22
1 0 0 1 1
Total 10 7 6 23 My question is:
1. Did i do the right thing to calculate probability?
2. Is that possible to have estimated probability from an empty cell?
I really appreciate your help on this, since my main goal is to develop the risk score using probability.
Thank you very much
0 Response to probability estimation using -margins- from zero cell in cross tabulation
Post a Comment