Hi all,
I am wondering if it is possible to generate a variable in the format of ith day of the year from a date variable. I have been reading about working with date variables in Stata, but have yet to find a solution to this problem.
So, using a small subset of the data for an example, I have:
date
07oct2003
01apr2005
07oct2003
30oct2003
01apr2005
01apr2005
29dec2003
30oct2003
30oct2003
01apr2005
And I am hoping to create a variable with values of:
day_of_year
280
91
280
303
91
91
363
303
303
91
I understand that this is complicated by leap years (2000, 2004, etc.), but I am hoping that Stata can automatically account for that somehow...
Any advice you might be able to offer would be greatly appreciated!
Best wishes,
Matt
Related Posts with Generating ith date of year variable from day/month/year date variable?
Predicted R-squaredAnyone know of a Stata command or user-written routine that generates the predicted R-squared after …
Plugging values of a variable back into StataHi users. I am using a variable called activity status which comes in codes such 11, 12, 21, 31, 41,…
Export cross tab with summary statisticsHi everyone, this seems like a super obvious question that I'm sure somebody has asked before, but …
How to deal with values that include numbers and lettersHello! I have a dataset that includes ICD10 codes, which include both numbers and letters (as seen i…
_cf mismatch on two datasets created by the same programHello, Why would it be the case that the same program (e.g. sales.do) used to generate the same dat…
Subscribe to:
Post Comments (Atom)
0 Response to Generating ith date of year variable from day/month/year date variable?
Post a Comment