Total sum of squares when using reg and noconstant

In the artificial data set below I estimated depvar = beta0 + beta1*year and depvar = beta1*year. Understood the formula for beta1 changes, but I would unerstand that total sum of squares is a function only of depvar, not how beta1 is estimated.

In the first case, the result makes sense as the sample mean of depvar is 10.5, so total sum of squares = 10*(0.5)^2 = 2.5.
In the second case, where I use the noconstant option, of course I expect the estimated beta1 to be different, but now the total sum of squares = 1105.

I see that TSS = 1105 if I pretend the sample mean of depvar = 0, but of course it remains as before, 10.5.

How does one get TSS = 1105 in the second estimation below? Pretend y-bar = 0
Then sum of (y – ybar)² = 5 * 10² + 5 * 11^2‑ = 500 + 605 = 1105.

Does anyone know why TSS is computed this way when the noconstant option is used?

. list

+-----------------------------------+
| userid depvar year plantype |
|-----------------------------------|
1. | 1 10 0 0 |
2. | 1 11 1 1 |
3. | 2 10 0 0 |
4. | 2 11 1 1 |
5. | 3 10 0 0 |
|-----------------------------------|
6. | 3 11 1 1 |
7. | 4 10 0 0 |
8. | 4 11 1 1 |
9. | 5 10 0 0 |
10. | 5 11 1 0 |
+-----------------------------------+

. reg depvar year

Source | SS df MS Number of obs = 10
-------------+---------------------------------- F(1, 8) = .
Model | 2.5 1 2.5 Prob > F = .
Residual | 0 8 0 R-squared = 1.0000
-------------+---------------------------------- Adj R-squared = 1.0000
Total | 2.5 9 .277777778 Root MSE = 0

------------------------------------------------------------------------------
depvar | Coef. Std. Err. t P>|t| [95% Conf. Interval]
-------------+----------------------------------------------------------------
year | 1 . . . . .
_cons | 10 . . . . .
------------------------------------------------------------------------------

. reg depvar year, noconstant

Source | SS df MS Number of obs = 10
-------------+---------------------------------- F(1, 9) = 10.89
Model | 605 1 605 Prob > F = 0.0092
Residual | 500 9 55.5555556 R-squared = 0.5475
-------------+---------------------------------- Adj R-squared = 0.4972
Total | 1105 10 110.5 Root MSE = 7.4536

------------------------------------------------------------------------------
depvar | Coef. Std. Err. t P>|t| [95% Conf. Interval]
-------------+----------------------------------------------------------------
year | 11 3.333333 3.30 0.009 3.459476 18.54052
------------------------------------------------------------------------------